Question 1121599

by definition, two angles are {{{complementary}}} when they add up to {{{90}}} degrees 

so, if angle {{{J}}} and angle {{{K }}}are complementary, we have:

{{{J+K=90}}}....eq.1

if angle {{{J}}} is{{{ 4}}} more than {{{3}}} times the measure of angle {{{K}}}, we have

{{{J=3K+4}}}....eq.2

substitute {{{J}}} from eq.2 in eq.1

{{{3K+4+K=90}}}....eq.1...solve for {{{K}}}

{{{4K=90-4}}}

{{{4K=86}}}

{{{K=86/4}}}

{{{K=21.5}}}


go to eq.2 and find {{{J}}}

{{{J=3*21.5+4}}}....eq.2

{{{J=64.5+4}}}

{{{J=68.5}}}