Question 101253
Convert the rectangular point (-8,8sqrt3) to polar coordinates with r>0.
r=sqrt(8^2+(8sqrt3)^2)= sqrt(256)= 16
theta = tan^-1((8sqrt3)/-8)=tan^-1(-sqrt3)=120 degrees or (2/3)pi
polar form: (16,(2/3)pi)
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(-16,(5/3)pi)
  
Also give two additional ways to represent this point in polar coordinates
 for which r<0 and -2pi<theta<=0,
(-16,(-pi/3)) 
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*and* r>0 and -2pi<theta<=0.
(16,((-4/3)pi))
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Cheers,
Stan H.