Question 1121563
Point  (0,y) equidistant from (5,1) and (-3,-1)


{{{sqrt((0-5)^2+(y-1)^2)=sqrt((0-(-3))^2+(y-(-1))^2)}}}


{{{sqrt(25+(y-1)^2)=sqrt(9+(y+1)^2)}}}


{{{25+(y-1)^2=9+(y+1)^2}}}


{{{16=(y+1)^2-(y-1)^2}}}


{{{16=y^2+2y+1-(y^2-2y+1)}}}


{{{16=y^2+2y+1-y^2+2y-1}}}


{{{16=4y}}}


{{{y=4}}}


The point is  (0,4).