Question 1121524
find mean and sd of the distribution
mean=np=450*0.65 or 292.5
variance is np(1-p) or 292.5*0.35 =102.375
sd is sqrt (V) or 10.02
z>(289.5-292.5)/10.02, using continuity correction factor of -0.5 to have z at least 290
z>-0.2994
probability is 0.6177