Question 101255
Let u=<-1,3> and v=<4,-6>. 
Find each of the following: 
a. 3u-2v = 3(-1,3)-2(4,-6)=(-3-8.9+12)=(-11,21)
b. The normalization of v:
|v|= sqrt(4^2+6^2) = sqrt52 = 2sqrt13
So, norm of v = (4/(2sqrt13),-6/(2sqrt13))
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Cheers,
Stan H.