Question 1121485
A question like this has too many possible answers.  You can choose any denominator you want.   "Show as many different solutions as you can."  This can be never ending.


Just one example.


{{{4&1/16+1&15/16=6}}}


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Maybe better:

Let some natural number d, be used as denominator.  For NUMERATOR of 1,

These examples will work:
{{{(3+1/d)+(2+(d-1)/d)=6}}}
or
{{{(4+1/d)+(1+(d-1)/d)=6}}}


but this example will not work according to your description:
{{{(5+1/d)+(d-1)/d=6}}}, because one of the numbers is not a mixed number.


You could also take this a make it more general than "numerator of 1".