Question 1120789
I would use x for year after 1994 (just to make the numbers go from 0 upward) and y for the tuition
For 2006 and 32218 (12, 32218) and 1994 (0, 11719)
change in y would be 32218-11719 or 20,499
change in x is 12
slope is 1708.25
use point slope formula y-y1=m(x-x1) m slope and (x1, y1) a point
1994 is easier because x=0
y-11719=1708.25(x-0)
y=1708.25x+11719
This is probably the best pair to choose, because it encompasses the ends of the data.  But any two points could be used to compare different linear models, and they would be done the same way.

One could say to prospective students for a given year x (say 2007) that the tuition would be about 11,700 (or 12,000) plus 13*1700.  Or, more simply for 2007, it would be about 1700 more than 2006 and so forth.  For 2010, 4 years after 2006 and 4*1708.25 is not far from 7000, one could add 7000 to the 2006 value.

For 2035, where x=41
y=1708.25*41+11719
This is $81757.25, and $80,000 would be an approximation to be given.  That assumes a great many things, most of which are not likely to happen.