<PRE><B>Question 1121380</B>
Find the center and radius of the following circle:
x2 + y2 - 12x + 8y - 29 = 0
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Complete the square for x and for y.
x^2 - 12x + y^2 + 8y - 29 = 0
x^2 - 12x + y^2 + 8y = 29
x^2 - 12x + 36 + y^2 + 8y + 16 = 29+36+16 = 81
(x-6)^2 + (y+4)^2 = 9^2
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(x-h)^2 + (y-k)^2 = r^2 is a circle - center at (h,k), radius r</PRE>