Question 1121376
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If 8.0 was the mean of 7 scores, then the total of the 7 scores must have been 56.  If 8.2 was the mean of 5 scores, then the total of the 5 scores must have been 41.  Therefore, the total of the highest score of the 7 plus the lowest score of the 7 must have been 15 (56 minus 41).  Since the most the highest score could have been was 10, the least the smallest score could have been was 5.
								
								
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
{{n}\choose{r}}
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