Question 1121374
integers are x, x+1, and x+2
x(x+1)=10(x+2)+2
x^2+x=10x+20+2
x^2-9x-22=0
(x-11)(x+2)=0
x=11, only positive result

11,12,13
product of first two is 132, which is 2 more than 10 times the third.