Question 1121189
Es (2x+1)(x-1)
Por eso 2x+1=0 y x=(-1/2) 
Y x-1=0 y x=1
{{{graph(300,300,-5,5,-10,10,2x^2-x-1)}}}
x=1, 2-1-1=0
x=-0.5, 0.5-(-0.5)-1; 1-1=0