Question 1121177
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<pre>
Let x be the number of P10 coins.


Then the number of P1 coins is (x+4), and the number of P5 coins is (3x+2).


The money equation then is


    (x+4) + 5*(3x+2) + 10x = 92


    x + 15x + 10x + (4 + 10) = 92


    26x = 92 - 14 = 78


    x = {{{78/26}}} = 3.


<U>Answer</U>.  3  P10 coins;  (3+4) = 7  P1 coins;  and  3x+2 = 3*3+2 = 11  P5 coins.


<U>Check</U>.   3*10 + 7*1 + 11*5 = 92.    ! Correct !
</pre>

Solved.


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<U>Be aware</U> : &nbsp;&nbsp;The solution by &nbsp;@josgaritmetic is &nbsp;&nbsp;<U>W R O N G</U>, &nbsp;&nbsp;starting from his very first equation.


For your safety, &nbsp;simply ignore it !