Question 1121168
{{{4p-11>=0}}}
{{{4p>=11}}}
{{{p>=11/4}}}------- a requirement


{{{p=4+sqrt(4p-11)}}}

{{{p-4=sqrt(4p-11)}}}

{{{p^2-8p+16=4p-11}}}

{{{p^2-12p+27=0}}}

{{{(p-3)(p-9)=0}}}

{{{highlight(p=9)}}}
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or
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{{{highlight(p=3)}}}