Question 1121162
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<pre>
Let  {{{alpha}}}  and  {{{beta}}}  be the roots to the second equation.


Then, according to Vieta's theorem,


    {{{alpha}}} + {{{beta}}} = - m;   {{{alpha}}}.{{{beta}}} = n.      (1)



According to the condition, the roots of the first equation are  {{{alpha^3}}}  and  {{{beta^3}}}.


Then, according to the Vieta's theorem


    p = {{{-(alpha^3 + beta^3)}}} = {{{-(alpha + beta)*(alpha^2-alpha*beta + beta^2)}}} = {{{-(alpha+beta)*((alpha+beta)^2-3alpha*beta)}}} = {{{m*(m^2-3n)}}},


    q = {{{alpha^3*beta^3}}} = {{{(alpha*beta)^3}}} = {{{n^3}}}.


<U>Answer</U>.  Under the given conditions,  p = {{{m*(m^2-3n)}}}  and  q = {{{n^3}}}.
</pre>

Solved.