Question 1120584
<br>
Given:
P(I) = 0.95
P(D) = 0.92<br>
So:
P(I') = 0.05
P(D') = 0.08<br>
Then
P(ID) = 0.95*0.92 = 0.874
P(ID') = 0.95*0.08 = 0.076
P(I'D) = 0.92*0.05 = 0.046
P(I'D') = 0.05*0.08 = 0.004<br>
Note the sum of all the probabilities is 1, which means the calculations are correct.<br>
You can answer the questions yourself....<br>
a) drawing in typed text doesn't work very well....
b) see above
c) see above