<PRE><B>Question 101124</B>
show that my=x^2-4(x-1) meets the curve y=x^2-3x+2 at two distinct points 
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y = x^2-4x+4 
y = x^2-3x+2
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Substitute to get:
x^2-4x+4 = x^2-3x+2
x= 2
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Substitute to solve for y:
y = 2^2-4*2+4
y = 0
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The curves meet at the point (2,0)
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Cheers,
Stan H.</PRE>