Question 1121146
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Passing through the point (6,3) and perpendicular to the line having x-intercept at -3 and y-intercept at 8
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Described given line is slope  {{{8/3}}}; and the line perpendicular wanted is of slope  {{{-3/8}}}.



{{{(y-3)/(x-6)=-3/8}}}
Adjust as necessary to put into form y=mx+b.