Question 1121063
The possible combinations are: (2,1) (2,3) (2,5) (3,1) (3,3) (3,5) (4,1) (4,3) (4,5).
Of these only (2,3) (3,1) (3,3) and (4,1) give sums greater than 3 and less than 7.
Thus the probability is 4/9