Question 1121004
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Let *[tex \Large x] represent the before tax charge in City #1.  Then *[tex \Large x\ -\ 1500] must be the before tax charge in City #2.


The amount of tax charged in City #1 is then *[tex \Large 0.035x] and the amount of tax charged in City #2 is *[tex \Large 0.03(x\ -\ 1500)]  These two amounts add up to $263.75.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 0.035x\ +\ 0.03(x\ -\ 1500)\ =\ 263.75]


Solve for *[tex \Large x], then calculate *[tex \Large x\ -\ 1500]
						
								
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
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