Question 1120983
.
<pre>
Let x = "How much did she invest in Fund B".


Then the amount she invested in fund A was (x-8000) dollars.


Fund A returned 0.03*(x-8000) dollars.


Fund B returned 0.07*x dollars.


According to the condition, 


    0.03*(x-8000) + 0.07x = 1960.


Simplify and solve for x.


    0.03x - 0.03*8000 + 0.07x = 1960

    0.1x = 1960 + 240 

    0.1x = 2200    ====>  x = {{{2200/0.1}}} = 22000.


<U>Answer</U>.  $22000 was invested in fund B.


<U>Check</U>.   0.03*(22000 - 8000) + 0.07*22000 = 1960  dollars.   ! Correct !
</pre>

Solved.


----------------


It is a typical and standard problem on investment.


If you want to learn on how to solve such problems on your own, &nbsp;look into the lesson

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/coordinate/lessons/Using-systems-of-equations-to-solve-problems-on-investment.lesson>Using systems of equations to solve problems on investment</A>

in this site.


You will find there different approaches &nbsp;(using one equation or a system of two equations in two unknowns), &nbsp;as well as 
different methods of solution to the equations &nbsp;(Substitution, &nbsp;Elimination).


Also, &nbsp;you have this free of charge online textbook in ALGEBRA-I in this site

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson>ALGEBRA-I - YOUR ONLINE TEXTBOOK</A>.


The referred lesson is the part of this online textbook under the topic &nbsp;"<U>Systems of two linear equations in two unknowns</U>".



Save the link to this online textbook together with its description


Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson


to your archive and use it when it is needed.