Question 1120806
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<pre>
Equation:


interest  + interest      = 460


0.10*x    + 0.12*(4000-x) = 460


Simplify and solve for x:


10x + 12*4000 - 12x = 460*100


-2x = 46000 - 12*4000


x      = {{{(46000-12*4000)/(-2)}}} =  1000 dollars  (amount invested at 10%)


4000-x = 3000 dollars  (amount invested at 12%)


<U>Check</U>.  0.10*1000 + 0.12*3000 = 460  dollars.   ! Correct</U> !


<U>Answer</U>.  $1000 invested at 10% and $3000 invested at 12%.
</pre>

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It is a typical and standard problem on investment.


To see many other similar solved problems on investment, &nbsp;look into the lesson

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/coordinate/lessons/Using-systems-of-equations-to-solve-problems-on-investment.lesson>Using systems of equations to solve problems on investment</A>

in this site.


You will find there different approaches &nbsp;(using one equation or a system of two equations in two unknowns), &nbsp;as well as 
different methods of solution to the equations &nbsp;(Substitution, &nbsp;Elimination).


Also, &nbsp;you have this free of charge online textbook in ALGEBRA-I in this site

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson>ALGEBRA-I - YOUR ONLINE TEXTBOOK</A>.


The referred lesson is the part of this online textbook under the topic &nbsp;"<U>Systems of two linear equations in two unknowns</U>".



Save the link to this online textbook together with its description


Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson


to your archive and use it when it is needed.