Question 101202
{{{2/3(p+3) > 5/6(p-4)}}}

If you multiply by 6 both sides, you will have:
{{{6*2/3(p+3) > 6*5/6(p-4)}}} 
=> {{{4(p+3)> 5(p-4)}}}  
=> {{{4p+12>5p-20}}}

=> {{{12 +20>5p-4p}}}
=> {{{32>p}}}

Or

{{{p<32}}}