Question 1120920
N=number of nickels
D=number of dimes<br>
Then
(1)  5N+10D = 215
(2)  D = 4+3N
<br>
Sub for D from (2) into (1):
5N + 10(4+3N) = 215

Solving, yields {{{highlight(N=5)}}} and plugging into (2) gives {{{highlight( D=19)  }}}
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Check:  5(5) + 10(19) = 25+190 = 215  (ok)
            and 4+3(5) = 4+15 = 19  (ok)