Question 1120869
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Here is a useful shortcut for solving this kind of problem:<br>
(1) every line parallel to the line with equation Ax+By=C (or Ax+By+C=0) will have an equation of the form Ax+By=D (or Ax+By+D=0), where D is some constant.
(2) every line perpendicular to the line with equation Ax+By=C (or Ax+By+C=0) will have an equation of the form Bx-Ay=D (or Bx-Ay+D=0), where D is some constant.<br>
In this example, the equation of the given line is 2x-3y+6 = 0.  The equation of any line perpendicular to the given line will have an equation of the form 3x+2y=D.<br>
To find the value of D, simply plug in the coordinates of the given point:<br>
{{{3(-2)+2(3)=D}}}
{{{D=0}}}<br>
An equation of the line we are looking for is 3x+2y=0.