Question 1120829
<br>
Since the problem asks for the number produced by plant B, it makes sense to make that our variable.  So<br>
let x = # produced by plant B
then x-6000 = # produced by plant A<br>
5% of those produced by plant B and 3% of those produced by plant A were defective, for a total of 1420.<br>
Write and solve the equation that says that:<br>
{{{.05(x)+.03(x-6000) = 1420}}}<br>
You can do the simple algebra....