Question 1120853
a customer bought a dozen of pieces of fruits (apples and oranges) for 1.32 dollars.
 If an apple cost 3 cents more than an orange and more apples than oranges were purchased,
 :
let p = cost of the oranges
then
(p+3) = cost of the apples
:
No. of apples are at least 7. (apples are more than the oranges)
let's try 8 apples 4 oranges, friendly numbers
8(p+3) + 4p = 132
8p + 24 + 4p = 132
8p + 4p = 132 - 24
12p = 108
p = 108/12
p = 9 cents for oranges
then
9 + 3 = 12 cents for apples
"How many pieces of each kind were bought? "
8 apples, 4 oranges