Question 1120869
Rewrite equation of line as 3y=2x+6 or y=(2/3)x+2
perpendicular line has negative reciprocal slope or -3/2
point-slope formula y-y1=m(x-x1) where m slope and (x1, y1) point
y-3=(-3/2)(x+2)
y-3=-(3/2)x-3
y=-3/2 x
{{{graph(300,300,-10,10,-10,10,y=(2/3)x+2,-3x/2)}}}