Question 1120847
{{{ 3x^2 - 12x = ( ax - b )^2 }}}
{{{ 3x^2 - 12x = a^2*x^2 - 2a*b*x + b^2 }}}
{{{ a^2 = 3 }}}
{{{ a = sqrt(3) }}}
{{{ -2a*b = -12 }}}
{{{ -2*sqrt(3)*b = -12 }}}
{{{ b = 6/sqrt(3) }}}
{{{ b^2 = 36/3 }}}
{{{ b^2 = 12 }}}
Add {{{ 12 }}} to make it a perfect square
{{{ ( sqrt(3)x - sqrt(12) )^2 = 3x^2 - 12x + 12 }}}