Question 1120845
{{{g(5)=(5+3)/(3-1)=8/2=4}}}
Perhaps you added in the denominator instead of subtracted (?)
{{{g(2n+1)=(2n+1+3)/(2n+1-1)=(2n+4)/(2n)=(2/2)((n+2)/n)=(n+2)/n=1+2/n}}}
Correct!