Question 1120765
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Overall you need to choose 4 of the 6 men; the number of ways is 6 choose 4 = 6C4 = 20.<br>
The requirement is that you choose 2 of a particular 2 men (2C2 = 1) AND 2 of the remaining 4 (4C2 = 6).<br>
The probability of getting a committee with the 2 particular men is
{{{(1*6)/20 = 3/10}}}