Question 101147
Start with the given distance formula

{{{d=sqrt((x[1]-x[2])^2+(y[1]-y[2])^2)}}} where *[Tex \Large \left(x_{1}, y_{1}\right)] is the first point *[Tex \Large \left(-4,0\right)] and *[Tex \Large \left(x_{2}, y_{2}\right)] is the second point *[Tex \Large \left(-5,-3\right)]


{{{d=sqrt((-4--5)^2+(0--3)^2)}}} Plug in {{{x[1]=-4}}}, {{{x[2]=-5}}}, {{{y[1]=0}}}, {{{y[2]=-3}}}


{{{d=sqrt((1)^2+(3)^2)}}} Evaluate {{{-4--5}}} to get 1. Evaluate {{{0--3}}} to get 3. 


{{{d=sqrt(1+9)}}} Square each value


{{{d=sqrt(10)}}} Add


So the distance approximates to


{{{d=3.16227766016838}}}


which rounds to

3.16


So the distance between (-4,0) and (-5,-3) is approximately 3.16 units