Question 101184
Factor completely:
{{{x^10y^3-4x^9y^2-21x^8y}}}Look for common factors in each term. You can see that {{{x^8y}}} is a common factor so factor this first:
{{{x^8y(x^2y^2-4xy-21)}}} Now factor the trinomial:
{{{x^8y(xy+3)(xy+7)}}}...and there you have it!