Question 1120633
the volume V of a given mass of mass [sic] gas varies directly as the temperature T and inversely as the pressure P. 
if V=232.0 in^3 when T=290 and P=15 psi, what is the volume when T=260 and P=20 psi? (round to the nearest tenth) 
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PV = nRT --> PV = k*T
k = PV/T = 15*232/290 = 12
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what is the volume when T=260 and P=20 psi?
PV = 12T
20V = 12*260 = 3120
V = 156