Question 1120603
If the diagonal of a swuare is 42.5cm long, find 
I) the perimeter
II) the area
Of the square
<pre>People like adding up don't have a clue about certain math problems. 
In addition, can the areas of 2 triangles that form a square have pretty much the same value as the square's hypotenuse: 42.51 cm<sup>2</sup> and 42.5 cm?
How can the perimeter of a square be SHORTER than the length of its hypotenuse? 
The square does form two 45-45-90 special triangles, but the {{{matrix(1,3, hypotenuse, "=", S * sqrt(2))}}}, with one side of the square being S
We can then say that: {{{matrix(1,10, S * sqrt(2), "=", 45, "=====>", S, "=", 45/sqrt(2), "=", 30.05, cm)}}}
You should now be able to find both the perimeter and area of the square.