Question 1120555
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Enclose the figure in a rectangle; then the area of the polygon is the area of the rectangle minus the area of the triangular regions that are outside the polygon and inside the rectangle.<br>
The area of each triangular region is one-half base times height.<br>
For the first one, the rectangle will be 4 wide and 3 high, with an area of 4*3=12.<br>
The three triangular regions have legs of 1 and 1 (area 1/2), 2 and 2 (area 2), and 4 and 1 (area 2).<br>
The area of the polygon is then 12 - (1/2+2+2) = 12 - 4 1/2 = 7 1/2<br>
The others can be solved the same way....