Question 1120548
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Draw the figure with station B 120km left (west) of station A, and the ship (point C) south of segment AB.  Draw the line CD indicating the (perpendicular) distance of the ship from the east-west line between the two stations.<br>
Let BC=x, so CA = 120-x.
Let d be the length of CD (the distance we are looking for).<br>
Segment CD makes two right triangles BDC and ADC.  In those triangles,<br>
tan(39) = x/d
tan(46) = (120-x)/d<br>
Eliminate x between those two equations to find d.  It should be easy if you see the right way to do it....