Question 1120523
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<pre>
2*log(2) - 2*log(5) = {{{log((2^2)) - log((5^2))}}} = {{{log((4)) - log((25))}}} = {{{log((4/25))}}} = {{{log(((4*4)/(25*4)))}}} = {{{log(((2^4)/100))}}} = {{{log((2^4)) - log((100))}}} = 4*log(2) - 2.
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