Question 1120479
the equation is -16t^2+44t+44
Maximum height occurs at t=-b/2a which is here -44/32 or 1.375 seconds ANSWER
This is 74.25 feet. ANSWER
{{{graph(300,300,-5,5,-25,100,-16x^2+44x+44)}}}
Because the object was thrown at a height of 44 feet, the time in the air is not symmetric around the highest point.
Setting h=0, -16t2+44t+44=0
-4t^2+11t+11=0=4t^2-11t-11
t=(1/8)(11+/- sqrt (121+176)); sqrt (297)=17.23
t=28.23/8 or 3.53 sec as only positive root\
-32(3.53)+44=-68.96 ft/sec downward or a velocity of 68.96 ft/sec.