Question 1120391
both lines pass through the point (10,-8).
slope of the first line is 5.
slope of the second line is -1/5.


use the point slope form of the equation to solve this.


point slope form is (y-y1) = m * (x-x1)
m is the slope
y1 is the y-coordinate of the point.
x1 is the x-coordinate of the point.


(y-y1) = m * (x-x1) becomes y+8 = 5 * (x-10)


simplify to get y + 8 = 5x - 50


subtract 5x from both sides of this equation and subtract 8 from both sides of this equation to get:


y - 5x = -50 - 8


simplify to get:


y - 5x = -58


multiply both sides of this equation by -1 to get:


-y + 5x = 58


place the x variable ahead of the y variable to get:


5x - y = 58


subtract 58 from both sides of the equation to get:


5x - y - 58 = 0


your solution is 5x - y - 58 = 0