<PRE><B>Question 1120446</B>
&lt;br&gt;
The other tutor didn&#39;t show a complete solution, so I don&#39;t know how much work remained to reach the answer from where they left off.  In any case, I get a different answer than they did....&lt;br&gt;
There are many different ways the problem can be set up; the method I used shown below may not be the easiest or most efficient....&lt;br&gt;
Let m be the mother&#39;s current age&lt;br&gt;
Then 100-m is Juanita&#39;s current age, since the sum of their ages is 100.&lt;br&gt;
Let s be the son&#39;s current age.&lt;br&gt;
The number of years until Juanita is her mother&#39;s current age is the difference of their current ages: m-(100-m) = 2m-100.&lt;br&gt;
According to the statement of the problem, m is Juanita&#39;s age &quot;then&quot;.&lt;br&gt;
The son&#39;s age &quot;then&quot; is s + (2m-100).&lt;br&gt;
Juanita &quot;then&quot; will be 5 times as old as her son is now:
(1) m = 5s.&lt;br&gt;
Her son&#39;s age &quot;then&quot; will be 8 more than Juanita&#39;s current age:
(2) s+2m-100 = 108-m  --&gt;  s+3m = 208.&lt;br&gt;
Substitute (1) in (2) to find s, the son&#39;s current age.&lt;br&gt;
s+3(5s) = 208
s+15s = 208
16s = 208
s = 13&lt;br&gt;
The son&#39;s current age is 13.
So the mother&#39;s current age is 5(13) = 65.
So Juanita&#39;s current age is 100-65 = 35.</PRE>