Question 1120371
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In order for there to be any kind of triangle, the sum of the lengths of the two shortest sides must be strictly greater than the longest side.  In order to have an isosceles triangle, two of the sides must be equal.
								
								
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
{{n}\choose{r}}

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