Question 1120345
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Just like multiplying any other fractions:  Numerator times numerator over denominator times denominator.  Then you need to collect like terms.


Hint:  Here you can simplify the problem before you perform the multiplication.  Factor the denominator in the left-hand fraction and the numerator in the right-hand fraction.  You will find that they have a factor in common that can be eliminated before the multiplication, greatly simplifying the arithmetic.
								
								
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
{{n}\choose{r}}

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