Question 1120328
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(a/b) / (c/d) = (a/b)*(d/c)<br>
So the expression is<br>
{{{((x^2+6x+5)/(3x^2-9x-12))*((2x^2+5x-3)/(2x^2+9x-5))}}} =
{{{((x^2+6x+5)(2x^2+5x-3))/((3x^2-9x-12)(2x^2+9x-5))}}}<br>
Factor each of the quadratic factors and simplify where possible.<br>
Note that it is easiest to factor the simpler quadratics first; hoping that the expression will simplify, that will give you ideas of how the more difficult quadratics will factor.<br>
{{{((x+1)(x+5)(2x-1)(x+3))/(3(x-4)(x+1)(2x-1)(x+5))}}} =
{{{(x+3)/(3(x-4))}}}<br>