Question 1120111
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \  P\ =\ \frac{40\ +\ 20x}{1\ +\ 0.05x}]


You want to know how many years (*[tex \Large x]) it will take the population *[tex \Large P] to be 200.  Set:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{40\ +\ 20x}{1\ +\ 0.05x}\ =\ 200]


Solve for *[tex \Large x]
								
								
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
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