<PRE><B>Question 1120112</B>
&lt;br&gt;
4x^3+6x^2 = 70x&lt;br&gt;
Get all terms on one side, with &quot;0&quot; on the other side:&lt;br&gt;
4x^3+6x^2-70x = 0&lt;br&gt;
Divide by the constant factor 2:&lt;br&gt;
2x^3+3x^2-35x = 0&lt;br&gt;
Factor out the common power of the variable:&lt;br&gt;
x(2x^2+3x-35) = 0&lt;br&gt;
Factor the remaining quadratic factor:&lt;br&gt;
x(2x-7)(x+5) = 0&lt;br&gt;
The solutions are when any of the factors on the left are zero:&lt;br&gt;
x = 0
2x-7 = 0  --&gt;  x = 7/2
x+5 = 0  --&gt;  x = -5&lt;br&gt;
Answer: The roots are -5, 0, and 7/2.</PRE>