Question 1120081
This is a one-tailed test which claims:
Ho: The percentage is <= 0.9
Ha: The percentage is > 0.9, so if Ho is rejected, we say the true proportion is >0.9.
Test statistic is z=(phat-p)/sqrt(p*(1-p)/n)
Critical value is z>1.645 for alpha of 0.05
z=0.07/sqrt(0.9*0.01/500)
z=0.07/0/013=5.22
Reject Ho 
p-value is 0.00 to two decimal places