Question 1120083
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ +\ y\ =\ 24]
*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ -\ y\ =\ 8]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ 16]
*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ =\ 8]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \cos(8^\circ)\ =\ \cos(16^\circ\ -\ \8^\circ)\ =\ \cos(16^\circ)\cos(8^\circ)\ +\ \sin(16^\circ)\sin(8^\circ)]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \cos(24^\circ)\ =\ \cos(16^\circ\ +\ \8^\circ)\ =\ \cos(16^\circ)\cos(8^\circ)\ -\ \sin(16^\circ)\sin(8^\circ)]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \cos(8^\circ)\ -\ \cos(16^\circ)\ =\ \(\cos(16^\circ)\cos(8^\circ)\ +\ \sin(16^\circ)\sin(8^\circ)\)\ -\ \(\cos(16^\circ)\cos(8^\circ)\ -\ \sin(16^\circ)\sin(8^\circ)\)]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ =\ 2\sin(16^\circ)\sin(8^\circ)]
								
								
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
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