Question 1120084
.
Solve the equation in the interval (0 degrees, 360 degrees)

sin^2 theta-sin theta-12=0
~~~~~~~~~~~~~~~


This equation has no real solutions.


See the plot below



{{{graph( 660, 660, -0.5, 6.5, -2.5, 15.5,
          sin(x)*sin(x)-sin(x),  12
)}}}


Plot  y = {{{sin^2(x)-sin(x)}}}  (red)   and  y = 12  (green)  on the interval  [0,{{{2pi}}}).