Question 1120023
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Since the condition does not state an opposite, I should assume that the apples are not distinguishable, same as the pears and the oranges.


So we have permutations of 7 fruits with 2 indistinguishable apples, 3 indistinguishable pears and 2 indistinguishable oranges.


The number of distinguishable arrangements is


    {{{7!/(2!*3!*2!)}}} = {{{(1*2*3*4*5*6*7)/(2*6*2)}}} =  210.


<U>Answer</U>.  There are 210 ways to do it.
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On this subject, &nbsp;see the lesson

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF =https://www.algebra.com/algebra/homework/Permutations/Arranging-elements-of-sets-containing-undistinguishable-elements.lesson>Arranging elements of sets containing indistinguishable elements</A> 

in this site.


Also, &nbsp;you have this free of charge online textbook in ALGEBRA-II in this site

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson>ALGEBRA-II - YOUR ONLINE TEXTBOOK</A>.


The referred lesson is the part of this online textbook under the topic &nbsp;"<U>Combinatorics: Combinations and permutations</U>". 



Save the link to this textbook together with its description


Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson


into your archive and use when it is needed.