Question 1120028
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Let *[tex \Large x] represent Jo's age.  Then *[tex \Large 3x] is Mary's age and *[tex \Large x\ -\ 5] is Larry's age.


The sum of their ages is 120 so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  3x\ +\ x\ +\ (x\ -\ 5)\ =\ 120]


Solve for *[tex \Large x] then calculate *[tex \Large 3x] and *[tex \Large x\ -\ 5]
								
								
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
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